ab(x^(2)+1)+x(a^(2)+b^(2))

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)

The square root of x^(b^(2))x^(b^(2)+2ab)x^(a^(2)-b^(2)) is

Find the value of (5a^(6))x(-10ab^(2))x(-2.1a^(2)b^(3)) for a=1 and b=(1)/(2)

Factorise : (x-1)^(2)a^(2)+2(x^(2)+1)ab+(x+1)^(2)b^(2)

If 2x = a + (1)/(a) and 2y = b + (1)/(b) , then prove that xy + sqrt((x^(2) -1) (y^(2) - 1)) = (1)/(2) (ab + (1)/(ab))

The angle of intersection of the curves (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and x^(2)+y^(2)=ab, is

Factorise the expression using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) x ^(2) + 2x + 1

Divide: (a^(2)+2ab+b^(2))-(a^(2)+2ac+c^(2))by2a+b+c(1)/(4)x^(2)-(1)/(2)x-12by(1)/(2)x-4