A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s . A body of 2kg weight is dropped from it. If `g = 10 m//s^(2)`, the body will reach the surface of the earth in

A balloon is at a height of 40 m and is ascending with a velocity of 10 "m.s"^(-1) . A bag of 5 kg weight is dropped from it. When will the bag reach the surface of the earth? Given g = 10 "m.s"^(-2) .

A balloon is at a height of 40 m and is ascending with a velocity of 10 ms^(-1) . A bag of 5 kg weight is dropped from it, when will the bag reach surface of earth ? (g = 10 m//s^(2))

A balloon is at a height of 40 m and is ascending with a velocity of 10 ms^(-1) . A bag of 5 kg weight is dropped from it, when will the bag reach surface of earth ? (g = 10 m//s^(2))

A body is projected upwards with a velocity of 19.6 m/s. Find the time of ascend. G = 9.8 m / s^2 .

A balloon is ringing up with constant velocity of 10 m/s. At a height of 75m a small mass is dropped from it. At what height from the ground would the balloon be when the mass reaches the ground?

Mass of a body is 50 kg. What is its weight on earth ( g=10 m//s^2 )

The weight of a body of mass 3 kg at a height of 12.8 xx 10^(6) m from the surface of the Earth is ______.

A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around : (takes the value of gas 10 m//s^2)

If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)