The lines `2x+3y+19=0` and `9x+6y-17=0` , cut the coordinate axes at concyclic points.

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

If the lines 2x+3y-1=0 and kx-y+4=0 intersect the coordinate axes in concyclic points then k-1=

If lines 2x-3y+6=0 and kx+2y=12=0 cut the coordinate axes in concyclic points, then the value of |k| is

If the lines x-2y+3=0,3x+ky+7=0 cut the coordinate axes in concyclic points, then k=

Suppose the lines x-2y+1=0mx+y+3=0' meet the coordinate axes in concyclic points then

If the line a_1 x + b_1 y+ c_1 = 0 and a_2 x + b_2 y + c_2 = 0 cut the coordinate axes in concyclic points, prove that : a_1 a_2 = b_1 b_2 .

8.If the lines a_(1)x+b_(1)y+c_(1)=0 and a_(2)x+b_(2)y+c_(2)=0 cuts the coordinate axes in concyclic points then

If the 4 points made by intersection of lines 2x-y+1=0,x-2y+3=0 with the coordinate axes are concyclic then centre of circle is (A) ((7)/(4),(5)/(4))(B)((7)/(4),(-5)/(4))(C)((-7)/(4),(5)/(4))(D)((-7)/(4),(-5)/(4))

Statement 1: If the lines 2x+3y+19=0 and 9x+6y-17=0 cut the x -axis at A,B and the y-axis at C,D, then the points,A,B,C,D are concyclic.Statement 2: since OAxOB=OCxOD, where O is the origin,A,B,C,D are concyclic.