(v)`(3)/(8)+(7)/(2)+((-3)/(5))+(6)/(5)-((-9)/(8))-(3)/(2)`

Simplify: (3)/(8)+(7)/(2)+(-3)/(5)+(9)/(8)+(-3)/(2)+(6)/(5)

The expression (5(5)/(8))/(6(3)/(7)) of (6(7)/(11))/(9(1)/(8))-:(8)/(9)(2(3)/(11)+(13)/(22)) of (3)/(5) equals (a) 1 (b) (1)/(2)( c) (7)/(9)( d) (5)/(12)

Solve (i) 2-(3)/(5)(ii)4+(7)/(8)(iii)(3)/(5)+(2)/(7)(iv)(9)/(11)-(4)/(5)(v)(7)/(10)+(2)/(5)+(3)/(2)(vi)(2)(2)/(3)+(3)(1)/(2) (vii) (8)(1)/(2)-(3)(5)/(8)

Write the set {(1)/(2),(2)/(3),(3)/(4),(4)/(5),(5)/(6),(6)/(7),(7)/(8),(8)/(9),(9)/(10)} in the set builder form.

(5)/(6)-:(6)/(7)xx?-(8)/(9)-:1(3)/(5)+(3)/(4)xx3(1)/(3)=2(7)/(9)(7)/(6)(b)(6)/(7)(c)1(d) None of these

Convert each of the following Into an improper fraction: (i) 5(5)/(7) (ii) 9(3)/(8) (iii) 6(3)/(10) (iv) 3(5)/(11) (v) 10(9)/(14) (vi) 12(7)/(15) (vii) 8(8)/(13) (viii) 51(2)/(3)

(3)/(2!)+(5)/(4!)+(7)/(6!)+(9)/(8!)+....=

(5)/(6) -: (6)/(7) xx ? - (8)/(9) -: 1 (2)/(5) -: (3)/(4) xx 3 (1)/(3) = 2(7)/(9)