Distance of point `(1,3)` from the line `2x-3y+9=0` along `x-y+1=0`

The distance of a point (2,3) from the line 2x-3y+9=0 measured along a line x-y+1=0 is

Find the distance of point (2,3) from the line 2x-3y+9=0 measured along a line making an angle of 4^(0) with the x -axis.

Find the distance of the point (2,3) from the line 2x-3y+9=0 measured along the line 2x-2y+5=0

Find the distance of the point (2,3) from the lilne 2x-3y+9=0 measured along a line x-y+1=0

The distance of the point (1,2) from the line x+y+5=0 measured along the line parallel to 3x -y=7 is equal to

Distance of a point (2,5) from the line 2x-y-4=0 measured parallel to the line 3x-4y+8=0 is :

The distance of the point (2, 3) from the line 4x-3y+26=0 is same as its distance from the line 3x-4y+p=0 . The value of p can be

If product of distance of point (1,2,-1) from planes 2x-3y+z+k=0 and x+2y+3z=0 is 1, then k is equal to