Home
Class 12
MATHS
The internal centre of similitude of two...

The internal centre of similitude of two circles `(x-3)^(2)+(y-2)^(2)-9,(x+5)^(2)+(y+6)^(2)=9` is

Promotional Banner

Similar Questions

Explore conceptually related problems

The internal centre of similitude of the two circles x^(2)+y^(2)+6x-2y+1=0 , x^(2)+y^(2)-2x-6y+9=0 is

The internal centre of similitude of the circles x^(2)+y^(2)-2x+4y+4=0,x^(2)+y^(2)+4x-2y+1=0 divides the segment joining their centres in the ratio

The external centre of similitude of the circle x^(2)+y^(2)-12x+8y+48=0 and x^(2)+y^(2)-4x+2y-4=0 divides the segment joining centres in the ratio

The centre and radius of the circle (x+ 2)^(2) + (y+4)^(2) = 9 are

If P(1, 1//2) is a centre of similitude for the circles x^(2)+y^(2)+4x+2y-4=0 and x^(2)+y^(2)-4x-2y+4=0 , then the length of the common tangent through P to the circles, is

If (-(1)/(3),-1) is a centre of similitude for the circles x^(2)+y^(2)=1 and x^(2)+y^(2)-2x-6y-6=0, then the length of common tangent of the circles is

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

Find the centre and radius of the circle 3x^(2) 3y^(2) - 6x +9y - 8 =0 .

Find the radical center of the circles x^(2)+y^(2)+4x+6y=19,x^(2)+y^(2)=9,x^(2)+y^(2)-2x-4y=5

Find the centre and radius of the circle x^(2)+y^(2)+10x-12y+9=0