If displacement of particle is `x=160t-16t^(2)`, then at t=1and t=9, velocities are

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

If displacement of particle is s=t^(3)-6t^(2)+9t+15, then velocity of the particle at beginning is

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is

The displacement x of a particle at time t is given by x=160t-16t^(2) . Show that its velocity at t = 1 amd t = 9 are equal in magnitude but opposite in directions.

If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then velocity of the particle at t=4 sec. is

The displacement x of a particle at a time t is given by x=160t-16t^(2) ,show that its velocity at t=1 and t=9 are equal in magnitude but opposite in direction.

The displacement x of a particle at time tis given by x= 160t-16t^2 . Show that its velocity at t=1 and t=9 are equal in magnitude but opposite in sign.

If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then displacement of the particle when velocity is (3)/(2) , is

If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then acceleration of the particle when its velocity is (3)/(2) , is

If the displacement of a particle varies with time as x = 5t^2+ 7t . Then find its velocity.