Assertion: In `y = A sin (omega t - kx),(omega t - kx)` is dimensionless.
Reason: Because dimension of `omega = [M^(0)L^(0)T]`.

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

y = A sin(omega t- kx) Cm this equation find out the dimension of omega ?

if y = A sin(omega t - kx) , then the value of (dy)/(dx) is

if y = A sin(omega t - kx) , then the value of (dy)/(dx) is

y_1 =4sin( omega t + kx), y2 = -4 cos( omega t + kx), the phase difference is

In the equation : y=a sin (omega t - kx), t and x stand for time and distnace respectively. Obtain the dimensional formula for omega and k.