A bar of iron is 10 cm at `20^(@)C`. At `19^(@)C` it will be `(alpha_(Fe)=11xx10^(-6)//.^(@)C)`

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be ( alpha of iron =11xx10^-6//^(@)C )

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be ( alpha of iron =11xx10.//^(@)C )

An iron sphere has a radius of 10 cm at a temperature of 0^(@)C . Calculate the change in volume of the sphere if it is heated to 100^(@)C . Given alpha_(Fe) = 1.1 xx 10^(-6).^(@)C^(-1)

What will be the stress at -20^(@) C, if a steel rod with a cross-sectional area of 150 mm^(2) is stretched between two fixed points? The tensile load at 20^(@) C is 5000 N (Assume, alpha=11.7xx10^(-6)//^(@)C and Y = 200 xx 10^(11) N//m^(2) )

What will be the stress at -20^(@) C, if a steel rod with a cross-sectional area of 150 mm^(2) is stretched between two fixed points? The tensile load at 20^(@) C is 5000 N (Assume, alpha=11.7xx10^(-6)//^(@)C and Y = 200 xx 10^(11) N//m^(2) )

A steel rod is 4000cm in diameter at 30^(@)C A brass ring has an interior diameter of 3.992cm at 30^(@) in order that the ring just slides onto the steel rod the common temperature of the two should be nearly (alpha_(steel)=11xx10^(-6)/(^(@)C) and alpha_(brass)=19xx10^(-6)/(^(@)C)

An iron plate has a circular hole of diameter 10 cm . Find the diameter of the hole when the plate is uniformly heated from 10^@C to 90^@C (alpha = 12 xx 10^(-6)//^@C) .