If we reduce `3x+3y+7=0` to the form `xcosalpha+ysinalpha=p ,` then find the value of `pdot`

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))

Reduce the equation y+4=0 to the normal form x cos alhpha+y sin alpha=p and hence find the values of alpha and p .

Reduce the equation sqrt3+y+2=0 to the normal form x cos alpha+y sin alpha=p , and hence find the value of alpha and p .

Reduce the equation sqrt3+y+2=0 to the normal form x cos alpha+y sin alpha=p , and hence find the value of alpha and p .

Reduce the equation x+sqrt3y-4=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

Reduce the equation x+y-sqrt2=0 to the normal form x cos alpha+y sin alpha=p , and hence find the values of alpha and p .

If 3x+5y =9 and 5x+3y=7, then find the value of x+y.

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

IF 3x +5Y = 9 and 5x + 3y =7 then find the value of x+y