If `(1+i)(1+2i)....(1+ix)=a+ib`, then `2.5....(1+x^2)` equals to

If (1+i)(1+2i)(1+3i)…...(1+ni) = a+ib , then 2.5.10…....(1+n^2) is equal to

If (1+i)(1+2i)(1+3i)......(1+ni)=a+ib,then2xx5xx10...(1+n^(2)) is equal to sqrt(a^(2)+b^(2))(b)sqrt(a^(2)-b^(2))(c)a^(2)+b^(2)(d)a^(2)-b^(2)(e)a+b

If (1+i)(1+2i)(1+3i)...(1+ni)=a+ib then 2xx5xx10xx...(1+n^(2))=

If (4+2i)(1+2i)=A+iB, then

If (1+i)(1+2i)(1+3i)....(1+ni)=a+ib then 2xx5xx10xx....xx(1+n^(2))=...

If (1+i)(1+2i)(1+3i)(1+ni)=a+ib then 2.5.10.17(1+n^(2))=a-ibba^(2)-b^(2)c*a^(2)+b^(2)d none of these

If (1+i)(2+i)(3+i)...(n+i)=a+ib show that, 2*5*10...(n^(2)+1)=a^(2)+b^(2).

If (1+i)(1+2i)(1+3i)"……."(1+ni)=a+ib," then "2xx5xx10xx"………"xx(1+n^2) is equal to

If x+iy=(1+i)(1+2i)(1+3i) , then x^(2)+y^(2) equals: