[" 17.यदि "sin theta=(p)/(sqrt(p^(2)+q^(2)))," तो सिद्ध कीजिए कि : "],[qquad q sin theta=p]

If sin theta= (p)/(sqrt(p^(2)+q^(2))) then prove that qsin theta=p cos theta

if : p*cos theta=sqrt(p^(2)+q^(2)).sin theta, "then" : q * sin theta=

5. sin p theta+sin q theta=0

If sin theta=(p^2-1)/(p^2+1) , then cos theta is equal to : यदि sin theta= (p^2-1)/(p^2+1) है, तो cos theta का मान है :

If sin theta=p and cos theta=q then find p^(2)+q^(2) is

Solve : cos p theta = sin q theta.

S_(1) : If tan p theta = cot q theta " then " theta = ((2 n + 1) pi)/( p (P + q)), n in Z S_(2) : If tan (pi sin theta ) = cot (pi cos theta) , " then " sin (theta + (pi)/(4)) = pm (1)/(2 sqrt(2))

ABCD is a trapezium such that AB and CD are parallel and BC bot CD . If angleADB = theta, BC = p and CD = q , then AB is equal to (a) ((p^(2)+q^(2))sin theta)/(p cos theta +q sin theta) (b) (p ^(2) + q ^(2)cos theta)/(p cos theta +q sin theta) (c) (p ^(2)+ q^(2))/(p^(2)cos theta +q^(2) sin theta) (d) ((p^(2) +q^(2))sin theta)/((p cos theta + sin theta)^(2))

If tan theta=(p)/(q) then (p sin theta-q cos theta)/(p sin theta+q cos theta)=

If tan theta=(p)/(q) then (p sin theta-q cos theta)/(p sin tehta+q cos theta)=