[" Q14The value of "2sin^(2)(3 pi)/(4)+2cos^(2)(pi)/(4)+2sec^(2)(pi)/(3)" is "],[[" (a) "10," (b) "8," (c) "0]]

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2sin^(2)quad (3 pi)/(4)+2cos^(2)(pi)/(4)+2sec^(2)(pi)/(3)=10

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2sin^2 (3pi)/4 +2cos^2 pi/4 +2sec^2 pi/3=10

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