x^(2)+6x-(a^(2)+2a-8)=0

Find the values of x satisfying log_(x^(2)+6x+8)log_(2x^(2)+2x+3)(x^(2)-2x)=0 is

If the circle x^(2) +y^(2) -6x -8y+( 25-a^(2) ) =0 touches the axis of x, then a equals.

If the circles x^(2) + y^(2) = a^(2) and x^(2) + y^(2) - 6x - 8y + 9 = 0 touches each other externally, then a = …….

Number of real values of x satisfying the equation log_(x^(2)+6x+8)(log_(2x^(2)+2x+3)(x^(2)-2x))=0 is equal to

For the given circles x^(2)+y^(2)-6x-2y+1=0 and x^(2)+y^(2)+2x-8y+13=0 , which of the following is true?