Prove that the area of the parallelogram contained by the lines `4y-3x-a=0,3y-4x+a=0,4y-3x-3a=0,` and `3y-4x+2a=0` is `(2/7)a^2dot`

Show that the area of the parallelogram formed by the lines x+3y-a = 0 , 3x-2y+3a=0, x + 3y +4a = 0 and 3x + 2y + 7a = 0 is 20/11 a^(2) sq units/

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is

The area of the parallelogram formed by the lines 3x+4y=7a;3x+4y=7b;4x+3y-7c and 4x+3y=7d is-

Prove that the diagonals of the parallelogram formed by the four lines 3x+y=0,3y+x=0,3x+y=4,3y+x=4 are at right angles.

The area of the parallelogram formed by the lines 3x-4y+1=0,3x-4y+3=0,4x-3y-1=0 and 4x-3y-2=0, is (A) (1)/(7) squnits (B) (2)/(7) squnits (C) (3)/(7) squnits (D) (4)/(7) squnits

The lines x+2y-5=0, 2x-3y+4=0,6x+4y-13=0

If area of the parallelogram formed by the lines x+3y-a=0, 3x-2y+3a=0, x+3y+4a=0 and 3x-2y+7a=0 is 220 sq. units, then value of a is ________

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+5=0 and 3x+4y-10=0 is equal to

Find the orthocenter of the triangle formed by the lines x + 2y = 0, 4x + 3y - 5 =0, 3x + y = 0 .