z=(1)/(1-cos theta-i sin theta)quad " then "R_(c)(z)

If z=(1)/(1-cos theta-i sin theta), then Re(z) is a.0 b.(1)/(2) c.cot((theta)/(2)) d.(1)/(2)cot((theta)/(2))

If z = (1)/(1 - cos theta - i sin theta), the Re (z)=

If z=1/(1-cos theta-i sin theta), then Re(z) is a. 0 b. 1/2 c. cot(theta/2) d. 1/2 cot (theta/2)

z=i+sqrt(3)=r(cos theta+sin theta)

The real part of z = (1)/(1-cos theta + i sin theta) is

If z = 1 - cos theta + i sin theta , then |z| =

If n is an integer and z=cos theta+i sin theta , then (z^(2 n)-1)/(z^(2 n)+1)=

If z= (cos theta, sin theta) , find (z-(1)/(z))

Let z_(1)=r_(1)(cos theta_(1)+i sin theta_(1)) and z_(2)=r_(2)(cos theta_(2)+i sin theta_(2)) be two complex numbers then prove the following