[" 21."(3)/(x)-(1)/(y)+9=0],[(2)/(x)+(3)/(y)=5quad (x!=0,y!=0)]

(3) / (x) - (1) / (y) + 9 = 0 (2) / (x) + (3) / (y) = 5, (! = 0, y! = 0)

( 3 ) /(x) - (1 ) /( y) + 9 = 0 , (2)/(x) + ( 3)/( y) = 5 ( x ne 0 , y ne 0 )

( 5)/(x)- ( 3) /( y ) = 1 , ( 3) /( 2 x ) + ( 2) /( 3y ) = 5 ( x ne 0 , y ne 0 )

If (2)/(x) + (3)/(y) = (9)/( xy ) and (4)/(x) + (9)/(y) = (21)/(xy) where x ne 0 and y ne 0, that what is the value of x + y ?

Solve the following system of equations: 2/x+3/y=9/(x y),\ \ \ 4/x+9/y=(21)/(x y),\ \ where x!=0,\ y!=0

Solution of D.E (dy)/(dx)=(2x+5y)/(2y-5x+3) is,if (y(0)=0) (1) x^(2)-y^(2)+5xy-3y=0 (2) x^(2)+y^(2)+5xy-3y=0 (3) x^(2)-y^(2)+5xy+3y=0 (4) x^(2)-y^(2)-5xy-3y=0

2(2x+y+5)+3(x-3y-1)=0 2x-3y+1=0

If one of the diagonals of a square is along the line x=2y and one of its vertices is (3, 0), then its sides through this vertex are given by the equations (A) y-3x+9=0, 3y+x-3=0 (B) y+3x+9=0, 3y+x-3=0 (C) y-3x+9=0, 3y-x+3=0 (D) y-3x+9=0, 3y+x+9=0

If one of the diagonals of a square is along the line x=2y and one of its vertices is (3, 0), then its sides through this vertex are given by the equations (A) y-3x+9=0, 3y+x-3=0 (B) y+3x+9=0, 3y+x-3=0 (C) y-3x+9=0, 3y-x+3=0 (D) y-3x+9=0, 3y+x+9=0