In Young's double slit experiment, the distance between sources is `1 mm` and distance between the screen and source is 1 m . If the fringe width on the screen is `0.06 cm` , then `lambda =`

In Young's double slit experiment, the distance between the two slits is 0.1 mm, the distance between the screen and the slit is 100 cm. if the width of the fringe is 5 mm, then the wavelength of monochromatic light used is

In Young's double slit experiment,the sepaation between the slit is halved and distance between the slits and screen is doubled.The fringe width is

In young's double slit experiment, if the distance between the slits is halved and the distance between the slits and the screen is doubled, the fringe width becomes

In Young's double slit experiment, the distance between two coherent sources is 1 mm and the distance between the slits and the screen is 1 m. If the 10th dark fringe is at a distance of 4.75 mm from the central bright fringe, calculate the distance of 5th bright fringe from the central bright fringe.

In Young's double slit experiment, the distance between two coherent sources is 1 mm and the distance between the slits and the screen is 1 m. If the 10th dark fringe is at a distance of 4.75 mm from the central bright fringe, calculate the wavelength of light used and

In Young's double-slit experiment using lambda=6000 Å , distance between the screen and the source is 1m. If the fringe-width on the screen is 0.06 cm, the distance between the two coherent sources is

In Young’s double slit experiment, the distance of screen is increased 4 times and distance between two coherent sources is reduced to half. The fringe width will

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is 4 xx 10^(-7) m . If the width of the fringe on the screen is 4 mm , the distance between screen and slit is