" ?.5"quad (x-5)(x-6)=(25)/((24)^(2))

Solve : (x-5)(x-6)=25/((24)^2)

5^(x)-24=(25)/(5^(x))

(x+5)/(2)+(x-5)/(3)=(25)/(6)

If x=3 and y=-1, find the values of each of the using identity: ((5)/(x)+5x)((25)/(x^(2))-25+25x^(2))

3x+(6)/(5)=6x+(3)/(25)

((2x) / (x-5)) ^ (2) +5 ((2x) / (x-5))-24 = 0

2x^(2)x3xy^(2)x4x^(3)y^(5) is equal to: 24x^(6)y^(6)(b)24x^(6)y^(7)24x^(7)y^(6)(d)24x^(7)y^(7)

Simplify (x^2-5)(x+5)+25

If sum_(i=1)^(5) (x_(i) - 6) = 5 and sum_(i=1)^(5)(x_(i)-6)^(2) = 25 , then the standard deviation of observations