A light ray coming along the line `3x+4y=5` gets reflected from the line `a x+b y=1` and goes along the line `5x-12 y=10.` Then, (A) `a=(64)/(115), b=(112)/(15)` (B) `a=(14)/(15), b=-8/(115)` (C) `a=(64)/(115), b=-8/(115)` (D) `a=(64)/(15), b=(14)/(15)`

Plot the line -3x-5y=15 .

Plot the line -3x-5y=15 .

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24x+7y+5=0. Find the equation of mirrors.

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light incident along the line 3x+(5-4sqrt(2))y=15 gets reflected from the hyperbola (x^(2))/(16)-(y^(2))/(9)=1 , then its reflected ray goes along the line

The distance of (1,2) from the line 3x-4y+15=0 measured parallel to the line 4x+3y=0 is

The distance of (1,2) from the line 3x-4y+15,=0 is measured parallel to the line 4x+3y=0is

The sides of a rhombus are parallel to the lines x+y-1=0 and 7x-y-5=0. It is given that the diagonals of the rhombus intersect at (1, 3) and one vertex, A of the rhombus lies on the line y=2x . Then the coordinates of vertex A are (a)(8/5,(16)/5) (b) (7/(15),(14)/(15)) (c)(6/5,(12)/5) (d) (4/(15),8/(15))