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" i) "(1)/(243)...

" i) "(1)/(243)

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If log_(x) ((1)/(243))=-5 , then find the value of x.

Express the following in exponential form. a. (256)/(10000) b. (-1)/(243)

The n^(th) term of the series 3, sqrt3, 1 -------is (1)/(243), then find n

If in a GP, 5th term and the 12th term are 9 and (1)/(243) respectively, find the 9th term of GP.

lim_(x rarr 3) (x^(-5)-(1)/(243))/(x-3)= _____.

3^((1)/(9)).9^((1)/(27)).27^((1)/(81)).81^((1)/(243))….oo=

((16)^((1)/(4)))/((27)^((1)/(3)))+((625)^((1)/(4)))/((81)^((1)/(4)))-(1)/((243)^((1)/(5)))=2

Find the value of : :((32)/(243))^((1)/(3))