[" Let "x=33^(n)" .The index "n" is given a positive "],[" integral value at random.The probability that "],[" the value of "x" will have "3" in the units place is "]

If x = 33^(n) , where n is a positive integral value, then what is the probability that x will have 3 at unit place?

If n is a positive integer then the probability that 3^(n) has 3 at unit place is

If n is a positive integer then the probability that 3^(n) has 3 at unit place is

If x^(n)-1 is divisible by x-k then the least positive integral value of k is

For every positive integral value of n, 3 ^(n) gt n^(3) when

if x^n - 1 is divisible by x - k , then the least positive integral value of k is

1000 ! Is divisible by 10^n . Find the largest positive integral value of n .

If x is an even number,then x^(4n), where n is a positive integer,will always have zero in the units place (b) 6 in the units place either 0 or 6 in the units place (d) None of these