6yquad gy^(2)-12y+2=0

9y^(2)-12y+2=0

The radical centre of the circles x^(2) + y^(2)- 2x + 6y = 0 , x^(2) + y^(2) - 4x - 2y + 6 = 0 , x^(2) + y^(2) - 12x + 12y + 30 = 0 is

The equation of the circle passing through the origin delta cutting the circles x^(2)+y^(2)-4x+6y+10=0 and x^(2)+y^(2)+12y+6=0 at right angles is -

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

Equation of the parabola whose focus is centre of the circle " x^(2)+y^(2)=4x+6y " and whose directrix is the line " x-y=0 " , is A) " x^(2)+y^(2)+2xy-8x-12y+26=0 " B ) " x^(2)+y^(2)-2xy-8x-12y-26=0 " C) " x^(2)+y^(2)+2xy+8x+12y+26=0 " D) " x^(2)+y^(2)-2xy-8x-12y+26=0 "

Equation of the parabola whose focus is centre of the circle " x^(2)+y^(2)=4x+6y " and whose directrix is the line " x-y=0 " is A) " x^(2)+y^(2)+2xy-8x-12y+26=0 B ) " x^(2)+y^(2)-2xy-8x-12y-26=0 C) " x^(2)+y^(2)+2xy+8x+12y+26=0 D) " x^(2)+y^(2)-2xy-8x-12y+26=0

Radii of circles x^(2) + y^(2) = 1, x^(2) + y^(2) - 2x - 6y= 6 and x^(2) + y^(2) - 4x - 12y = 9 are in

Prove that the radi of the circles x^(2)+y^(2)=1x^(2)+y^(2)-2x-6y=6 and x^(2)+y^(2)-4x-12y=9 are in arithmetic progression.