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21times[19=(......)^(2)-(.....)^(2)...

21times[19=(......)^(2)-(.....)^(2)

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21xx19=(...)^2-(...)^2

If sum_(k=1)^(12)12kquad 12C_(k)^quad 11C_(k-1) is equal to (12times21times19times......3)/(11!)times2^(12)times P then P is

If P=21(21^(2)-1^(2))(21^(2)-2^(2))...(21^(2)-10^(2)) , then p is divisible by-

If sum_(k=1)^(12)12k^(12)C_(k)^(11)C_(k-1) is equal to (12times21times19times)/(11!)times2^(12)times P then P is

Verify: (-21)times[(-4)+(-6)=[(-21)times(-4)]+[(-21)times(-6)]

Verify: (-21)times[(-4)+(-6)=[(-21)times(-4)]+[(-21)times(-6)]

If P = 21(21^2-1^2)(21^2-2^2)(21^2-3^2)...............(21^2-10^2),t h e nP is divisible by a. 22 ! b. 21 ! c. 19 ! d. 20!

If P = 21(21^2-1^2)(21^2-2^2)(21^2-3^2)...............(21^2-10^2),t h e nP is divisible by a. 22 ! b. 21 ! c. 19 ! d. 20!

If P = 21(21^2-1^2)(21^2-2^2)(21^2-3^2)...............(21^2-10^2),t h e nP is divisible by a. 22 ! b. 21 ! c. 19 ! d. 20!

If P = 21(21^2-1^2)(21^2-2^2)(21^2-3^2)...............(21^2-10^2),t h e nP is divisible by a. 22 ! b. 21 ! c. 19 ! d. 20!