If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that `1/(p^2)=1/(a^2)+1/(b^2)` .

If p is the length of perpendicular from the origin onto the plane whose intercepts on the axes area a,b,c then (A) a+b+c=p (B) a^-2+b^-2+c^-2=p^(-2) (C) a^(-1)+b^(-1)+c^(-1)=p^(-1) (D) a^(-1)+b^(-1)+c^(-1)=1

The length of perpendicular from the origin on the line x/a + y/b = 1 is -

If 'p' be the measure of the perpendicular segment from the origin on the line whose intercepts on the axes are 'a' and 'b'.then prove that : (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2))

If p is the length of the perpendicular from the origin to the line,whose intercepts with the coordinate axes are (1)/(3) and (1)/(4), then the value of p is :

p is the length of the perpendicular drawn from origin to the line whose intercepts on axis is a and b,then relation between a,b and p is:

If p be the length of the perpendicular from the origin on the straight line x+2by=2p then what is the value of b?