`5(17)/(37)xx4(51)/(52)xx11(1)/(7)+2(3)/(4)=?`

6(6)/(6)xx5(1)/(3)+17(2)/(3)xx4(1)/(4)=?

17(2)/(5)xx4(5)/(8)-?=46(7)/(8)

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)

The sum of (7)/(2xx3)((1)/(3))+(9)/(3xx4)((1)/(3))^(2)+(11)/(4xx5)((1)/(3))^(3)+ upto 10 terms is equal to

(2^((1)/(2))xx3^((1)/(3))xx4^((1)/(4)))/(10^(-(1)/(5))xx5^((3)/(5)))-:(3^((4)/(3))xx5^(-(7)/(5)))/(4^(-(3)/(5))xx6)=10

The value of ((2/5)^(3)xx(1/7)^(3))/((2/5)^(2)xx(1/7)^(4)) is

Simplify and write the following in the exponential form: (i) ((-3)^(5)xx4^(6)xx4)/((-3)^(2)xx4^(9)) (ii) (11^(4)xx17^(3)xx19^(5))/(11^(2)xx17^(2)xx19^(2))

Evaluate : a. (-1)^(11) b. (-3)^(2)xx(5)^(3) c. 6^(2)xx3^(3) d. (-2)^(3)xx(-5)^(2) e. (-1)^(7)xx2 f. (-1)^(4)xx(-1)^(5) g. 4^(3)xx3^(4) h. (-2)^(5)xx5^(3) i. (-4)^(3)xx(-6)^(3) j. (-1)^(33)xx(-3)^(1) k. ((-1)/(6))^(2) l. ((2)/(11))^(3)