Find the foot of the perpendicular from the point `(2,4)` upon `x+y=1.`

Find the foot of the perpendicular from the point (-1,2) on the st. Line x-y+5=0 .

Find the foot of the perpendicular from the point (0,2,3) on the line (x+3)/(5)=(y-1)/(2)=(z+4)/(3) . Also,find the length of the perpendicular.

(a) Find the foot of the perpendicular from the point (i) (2, -1,5) on the line : (x -11)/(10) = (y + 2)/(-5) = (z + 8)/(11) (ii) (0,2,3) on the line (x +3)/(5) = (y-1)/(2) = (z + 4)/(3) . (b) Also, find the length of perpendicular in part (ii).

Find the foot of the perpendicular from the point (2,3,-8) to the line (4-x)/(2)=(y)/(6)=(1-z)/(3). Find the perpendicular distance from the given point to the line.

The co-ordinates of foot of the perpendicular from the point (2,4) on the line x+y=1 are:

(I) Find the foot and length of the perpendicular from the point (3,4,5) to the plane : 2 x - 5y + 3z = 39 . (ii) Find the length and the foot of the perpendicular from the point (7,14,5) to the plane 2x + 4y - z = 2 .

Find the length of the perpendicular drawn from the point (4,5) upon the straight line 3x+4y=10

The coordinates of the foot of the perpendicular drawn from the point (3,4) on the line 2x +y-7 =0 are