In `triangleABC`, vertex A is (1, 2). If the internal angle bisector of `angle B` is `2x- y+10=0` and the perpendicular bisector of AC is y = x, then find the equation of BC

In /_ABC, vertex A is (1,2). If the internal angle bisector of /_B is 2x-y+10=0 and the perpendicular bisector of AC is y=x ,then find the equation of BC

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

Let in DeltaABC the coordinates of A are (0, 0). Internal angle bisector of angle ABC is x-y+1=0 and mid - point of BC is (-1, 3) . Then, the ordinate of C is

In a triangle ABC, A(3,5) is the vertex. If the internal angle bisector of B is y=x then which of the following point must be lie on line BC .

Let in DeltaABC coordinates of vertex A is (0,0). Equation of the internal angle bisector of /_ABC is x + y - 1 = 0 and mid-point of BC is (1,3). The ordinate of vertex C is

Let A B C be a triangle. Let A be the point (1,2),y=x be the perpendicular bisector of A B , and x-2y+1=0 be the angle bisector of /_C . If the equation of B C is given by a x+b y-5=0 , then the value of a+b is (a)1 (b) 2 (c) 3 (d) 4

Consider a triangle ABC with vertex A(2,-4). The internal bisectors of the angle B and C are x+y=2 and x-3y=6 respectively.Let the two bisectors meet at I .I . (a,b) is incentre of the triangle ABC then (a+b) has the value equal to

The joint equation of bisectors of angles between lines x=5 and y=3 is

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc

Let the equations of side BC and the internal angle bisector of angle B of DeltaABC are 2x-5y+a=0 and y+x=0 respectively. If A=(2, 3) , then the value of of a is equal to