What will be normality of the resultant solution when 500 ml `1 N H_2SO_4`, 300 ml `HCl` and 200 ml `5N HNO_3` are mixed together and then volume was made 2000 ml by adding some water ?

Options

A. 0.9 N
B. 2 N
C. 1.9 N
D. 4 N

Answer

To find the normality of the resultant solution when mixing 500 ml of 1 N H₂SO₄, 300 ml of HCl, and 200 ml of 5 N HNO₃, and then diluting the mixture to a final volume of 2000 ml, we can follow these steps:

### Step-by-Step Solution:

1. **Calculate the equivalents of each acid:**
- For H₂SO₄:
- Normality (N) = 1 N
- Volume (V) = 500 ml = 0.5 L
- Equivalents = N × V = 1 N × 0.5 L = 0.5 equivalents

- For HCl:
- Normality (N) = 1 N (assuming it is 1 N since not specified)
- Volume (V) = 300 ml = 0.3 L
- Equivalents = N × V = 1 N × 0.3 L = 0.3 equivalents

- For HNO₃:
- Normality (N) = 5 N
- Volume (V) = 200 ml = 0.2 L
- Equivalents = N × V = 5 N × 0.2 L = 1.0 equivalents

2. **Total equivalents of the mixture:**
- Total equivalents = Equivalents of H₂SO₄ + Equivalents of HCl + Equivalents of HNO₃
- Total equivalents = 0.5 + 0.3 + 1.0 = 1.8 equivalents

3. **Calculate the normality of the resultant solution:**
- The final volume of the solution after dilution = 2000 ml = 2 L
- Normality (N) = Total equivalents / Total volume in liters
- Normality (N) = 1.8 equivalents / 2 L = 0.9 N

### Final Answer:
The normality of the resultant solution is **0.9 N**.

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