A block moves down a smooth inclined plane of inclination `theta`. Its velocity on reaching the bottom is v. If it slides down a rough inclined plane of some inclination, its velocity on reaching the bottom is v/n, where n is a number greater than 0. The coefficient of friction is given by -

Options

A. `mu = tan theta(1-1/(n^2))`
B. `mu = cot theta(1-1/(n^2))`
C. `mu = tan theta(1-1/(n^2))^(1//2)`
D. `mu = cot theta(1-1/(n^2))^(1//2)`

Answer

A