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Frequencies of various radiations are gi...

Frequencies of various radiations are given as
`f_(v) to` Visible light
`f_(r ) to` Radio waves
`f_(uv) to` Ultra Violet waves
The which of the following is true?

A

`f_(uv) = f_(v) lt f_(r )`

B

`f_(r) lt f_(v) lt f_(uv)`

C

`f_(v) , f_(r) lt f_(uv)`

D

`f_(uv) , f_(r ) lt f_(v )`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to compare the frequencies of various types of electromagnetic radiation: visible light (f_v), radio waves (f_r), and ultraviolet waves (f_uv). ### Step-by-Step Solution: 1. **Understanding the Electromagnetic Spectrum**: - The electromagnetic spectrum is divided into different regions based on wavelength and frequency. The regions include gamma rays, X-rays, ultraviolet (UV) light, visible light, infrared, microwaves, and radio waves. 2. **Identifying Wavelength Ranges**: - **Ultraviolet (UV)**: Wavelengths shorter than visible light, typically from about 10 nm to 400 nm. - **Visible Light**: Wavelengths range from approximately 400 nm (violet) to 700 nm (red). - **Radio Waves**: Wavelengths are much longer, starting from about 1 mm to several kilometers. 3. **Frequency and Wavelength Relationship**: - The frequency (f) of electromagnetic radiation is inversely proportional to its wavelength (λ) as described by the equation: \[ c = f \cdot \lambda \] where \(c\) is the speed of light (approximately \(3 \times 10^8\) m/s). - This means that as the wavelength increases, the frequency decreases. 4. **Comparing Frequencies**: - Since UV light has the shortest wavelength, it has the highest frequency. - Visible light has a longer wavelength than UV, so its frequency is lower than that of UV light. - Radio waves have the longest wavelengths and therefore the lowest frequencies. 5. **Conclusion**: - Based on the above analysis, we can establish the order of frequencies: \[ f_{uv} > f_{v} > f_{r} \] - Therefore, the correct statement is that the frequency of ultraviolet waves (f_uv) is greater than that of visible light (f_v), which in turn is greater than that of radio waves (f_r). ### Final Answer: The correct order of frequencies is: \[ f_{uv} > f_{v} > f_{r} \]
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