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In Young's double experiment , in air ...

In Young's double experiment , in air interference pattern second minimum is observed exactly in front of one slit. The distance between the two coherent source is 'd' and the distance between source and screen 'D'. The wavelength of light source used is

A

`(d^2)/D`

B

`(d^2)/(2D)`

C

`(d^2)/(3D)`

D

`(d^2)/(4D)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • An interference pattern is observed by Young's double slit experiment.If now the separation between coherent source is halved and the distance of screen from coheren sources is doubled, then now fringe width

    A
    becomes double
    B
    becomes ne-fourth
    C
    remains same
    D
    becomes four times

  • In Young's double slit experiment the two slits are d distance apart. Interference pattern is observed on a screen at a distance D from the slits. A dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light is

    A
    `(D^(2))/(2d)`
    B
    `(d^(2))/(2D)`
    C
    `(D^(2))/(d)`
    D
    `(d^(2))/(D)`

  • In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :

    A
    Half
    B
    Four times
    C
    One-fourth
    D
    Double

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