The mass of man when standing on the lift is 60 kg. The weight when the lift is moving upwards with acceration `4.9 ms^(-2)` is

Options

A. 882 N
B. 600 N
C. 306 N
D. zero

Answer

To solve the problem, we need to calculate the apparent weight of a man standing in a lift that is accelerating upwards. The apparent weight can be determined using the following steps:

### Step-by-Step Solution:

1. **Identify the Given Data**:
- Mass of the man, \( m = 60 \, \text{kg} \)
- Acceleration of the lift, \( a = 4.9 \, \text{m/s}^2 \)
- Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \)

2. **Understand the Forces Acting on the Man**:
- The weight of the man acting downwards: \( W = mg \)
- The upward force due to the lift's acceleration: \( F_{\text{up}} = ma \)

3. **Calculate the Weight of the Man**:
\[ W = mg = 60 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 588 \, \text{N} \]

4. **Calculate the Apparent Weight**:
- When the lift is accelerating upwards, the apparent weight (normal force \( N \)) can be calculated using the formula:
\[ N = mg + ma \]
- Substitute the values:
\[ N = 60 \, \text{kg} \times 9.8 \, \text{m/s}^2 + 60 \, \text{kg} \times 4.9 \, \text{m/s}^2 \]
\[ N = 588 \, \text{N} + 294 \, \text{N} = 882 \, \text{N} \]

5. **Conclusion**:
- The apparent weight of the man when the lift is moving upwards with an acceleration of \( 4.9 \, \text{m/s}^2 \) is \( 882 \, \text{N} \).

### Final Answer:
The weight of the man when the lift is moving upwards with an acceleration of \( 4.9 \, \text{m/s}^2 \) is **882 N**.