The density of KBr is `2.73"g cm"^(-3)`. The length of the unit cell is 654 pm. Predict the nature of the unit cell. (Given atomic mass of K = 39, Br = 80)

The density of KBr is 2.73g//cm . The length of the unit cell is 654p m . Find the number of atoms per unit cell in the cubic structure.

The density of KBr is 2.73 g/cm. The length of the unit cell is 654 pm. Find the number of molecules per unit cell in the cubic structure.

Density of KBr is 2.75 g//cm^(3) . The edge length of unit cell is 654 pm. Find the type of unit cell of KBr. (At mass of K = 39 and Br = 80).

The density of KBr is 2.75"gm cm"^(-3) . The edge length of unit cell is 654 pm. Predict the type of cubic lattice to which unit cell of KBr belongs. (N_(0)=6xx023xx10^(23)"mol"^(-1)) . Atomic mass of K = 39, Br = 80.

The density of KBr is 2.75 g cm^(-3) . The length of edge of unit cell is 654pm. Predict the type of cubic lattice to which unit cell of kBr belongs.

The density of KBr is 2.75 g cm^(-3) . The length of the unit cell is 654 pm. (Given atomic mass of K=39, Br=80). The number of formula units of KBr per unit cell are :

Density of KBr is 2.75 g//cm^3 . The edge length of unit cell is 654pm. Find the type of unit cell of KBr (At.mass of K=39 and Br=80)

The density of KBr is 2.75 gm cm^-3 length of the unit cell is 654 pm . K=39,Br=80, then what is true about the predicted nature of the solid: