Find the position of the point P on seg AB of length 8 cm, so that `"AP"^(2)+"BP"^(2)` is minimum.

To find a point P on the line segment AB = 6 cm, such that (AP)/(AB) = (2)/(5) , in which ratio the line segment AB is divided.

If P is midpoint of seg AB and AB = 7 cm, find AP.

A line segment AB of length 16 is divided into two part AP and PB by a point P .If AP ^(2)+ PB^(2) is minimum, then

.Point M is the midpoint of Seg AB.If AB=8 then find the length of AM.

Point M is the midpoint of seg AB. If AB= 8, then find the length of AM.

ABCD is a rectangle in which AB= 9cm, BC=6cm. P is a point in CD such that PC = xcm, then the value of x when AP^2 + BP^2 is minimum is

Point M is the mid point of seg AB. If AB = 8 then find the length of AM.