`(4times-6)-:(-2)`

(9)/(2)-:(7)/(5)times(4)/(6)-:(2)/(3)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

Evaluate: (-3) times (-4) times (-6) times 7 times (-2)

(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

(d) ((-5)/(8))times((3)/(4)xy)times((-6)/(5)x^(2)y)

11(1)/(4)-:3(3)/(5)times6(2)/(3)+(1)/(6)=

Solve : (-2 ) times (-3 ) times (-4 ) times (-5 ) times (-6 )

Is [(-2)times6]times4 = (-2)times[(6times4)] ?