For all `n in N, cos theta cos 2theta cos 4theta ....cos2^(n-1)theta` equals to

If theta=pi/(2^n+1) then cos theta cos 2 theta cos 2^(2) theta...... Cos2^(n-1) theta is equal to

If theta =(pi)/(2 ^(n) +1), then cos theta cos 2 theta cos 2^(2) theta …cos 2 ^(n-1)theta is equal to ................... A) (1)/(2 ^(n)) B) cos theta C) 2 D) 2^(n)

If theta =(pi)/(2 ^(n) +1), then cos theta cos 2 theta cos 2^(2) theta …cos 2 ^(n-1)theta is equal to

If theta=pi/(2^n+1) then costhetacos2thetacos2^2theta....cos2^(n-1)theta is equal to

cos theta+cos2 theta+cos3 theta+......+cos(n-1)theta+cos n theta=

If (2^n+1)theta=pi then 2^n costheta cos2theta cos2^2 theta .......cos 2^(n-1) theta=

cos theta + cos 2 theta + cos 3 theta + …. + cos { (n-1) theta}+ cos n theta=

Using induction, prove that cos theta · cos 2theta · cos 2^2 theta. ... cos 2^(n-1) theta =(sin2^n theta)/(2^n sin theta)

If theta = pi/(2^(n) + 1), "show that",2^(n) cos theta cos 2 theta cos2^(2) theta cos2^(3) theta.... cos2^(n-1) theta = 1.