If a pair of perpendicular straight lines drawn through the origin forms an isosceles triangle with the line `2x+3y=6` , then area of the triangle so formed is (a) `36/13` (b) `12/17` (c) `13/5` (d) `17/14`

Two mutually perpendicular straight lines through the origin from an isosceles triangle with the line 2x+y=5. Then the area of the triangle is

Drawn from origin are two mutually perpendicular lines forming an isosceles triangle together with the straight line 2x+y=a then the area of this triangle is

Two lines are drawn through (3,4), each of which makes angle of 45^(@) with the line x-y = 2 . Then area of the triangle formed by these lines is

Combined equation of the two lines passing through the origin, forming an equilateral triangle with the line x+y+sqrt(3)=0 is

A pair of perpendicular straight lines is drawn through the origin forming with the line 2x+3y=6 an isosceles triangle right-angled at the origin.The equation to the line pair is 5x^(2)-24xy-5y^(2)=05x^(2)-26xy-5y^(2)=05x^(2)+24xy-5y^(2)=05x^(2)+26xy-5y^(2)=0

Consider the lines y=3x, y=6x and y=9 What is the area of the triangle formed by these lines ?

If the lines 2x-y=8,x-2y=17 and line L=0 form an isoceles triangle,then slope of line L can be