The image of `P(a ,b)` on the line `y=-x` is `Q` and the image of `Q` on the line `y=x` is `R` . Then the midpoint of `P R` is (a) `(a+b ,b+a)` (b) `((a+b)/2,(b+2)/2)` (c) `(a-b ,b-a)` (d) `(0,0)`

The image of the point P(3,5) with respect to the line y=x is the point Q and the image of Q with respect to the line y=0 is the point R(a,b), then (a,b) is equal to:

The point Q is the image of the P in line x+y+4=0 and R is the image of Q in line 2x-y+7=0. If P=(1,6), then the circumcentre of triangle PQR is

The reflection of point P(2,-1) in line y=3x-1 is Q and reflection of P in line y=9-2x is R .thencircumcentre of APQR is (a,b), where (a+b) is equal to

If R(x,y) is a point on the line segment joining the points P(a,b) and Q(b,a), then prove that x+y=a+b

If (x_1, y_1)&(x_2, y_2) are the ends of diameter of a circle such that x_1&x_2 are the roots of the equation a x^2+b x+c=0 and y_1&y_2 are the roots of the equation p y^2+q y+c=0 . Then the coordinates f the centre of the circle is: (b/(2a), q/(2p)) (b) (-b/(2a),=q/(2p)) (b/a , q/p) (d) None of these

Locus of the image of a point A(0,0) in the line (2a+b)x+(3a-2b)y+(b-5a)=0 is (where a and b are parameters).

If the lines x+a y+a=0,\ b x+y+b=0\ a n d\ c x+c y+1=0 are concurrent, then write the value of 2a b c-a b-b c-c adot

P(a,b) is the midpoint of a line segment between axes.Show that equation of the line is (x)/(a)+(y)/(b)=2