If `e_(1),e_(2),e_(3)" and "e_(4)` are the four elementary outcomes in a sample space and `P(e_(1))=0.1,P(e_(2))=0.5,"and "P(e_(3))=0.1,` then the probability of `e_(4)` is ……

If E_(1),E_(2),E_(3) and E_(4) are the four elementary outcomes in a sample space and P(E_(1))=0.1,P(E_(2))=0.5,P(E_(3))=0.1 , then the probability of E_(4) is ……….

Let E_(1) and E_(2) are the two independent events such that P(E_(1))=0.35 and P(E_(1) uu E_(2))=0.60 , find P(E_(2)) .

If P(E)=0-8, P(F)=0.5 and P(F/E)=0.4 , then P(E/F)=

E_(1) and E_(2) are two independent events such that P(E_(1))=0.35 and P(E_(1) cup E_(2))=0.60 , find P(E_(2)) .

If E_(1) and E_(2) are two events associated with a random experiment such that P(E_(2))=0.35,P(E_(1) or E_(22))=0.85 and P(E_(1) and E_(2))=0.15 then P(E_(1)) is (A).25(B).35(C).65(D).75

Suppose E_1 and E_2 are two events of a sample space such that P(E_1)=1/2, P(E_2|E_1)=1/2, P(E_1|E_2)=1/4 then P(E'_2) = _____

A probability experiment has 4 possible outcomes e_(1),e_(2),e_(3), and e_(4) . The outcome e_(1) is four times as likely as each of the other 3 remaining outcomes. Find probability of e_(1) ?