In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=y and y=0.` If `A` is `(1,2)` , then the equation of line `B C` is (a) `2x+y=1` (b) `3x-y=5` (c) `x-2y=3` (d) `x+3y=5`

Equation of the bisector of angle B of the triangle ABC is y=x. If A is (2,6) and B is (1,1); equation of side BC is (A)2x+y-3=0 (B) x-5y+4=0 (C) x-6y+5=0 (D) none of these

Given ABCD is a parallelogram wilth vertices as A(1,2),B(3,4) and C(2,3) . Then the equation of line AD is (A) x+y+1=0 (B) x-y+1=0 (C) -x+y+1=0 (D) x+y-1=0

The area of triangle formed by the lines 2x-y+1=0 , 3x-y+5=0 and 2x-5y+11=0

If 2x+y-4=0 is bisector of the angle between the lines a(x-1)+b(y-2)=0,c(x-1)+d(y-2)=0 then other bisector is

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0

The equation of the bisector of the acute angle between the lines 2x-y+4=0 and x-2y=1 is (a) x-y+5=0 (b) x-y+1=0( c) x-y=5 (d) none of these

. If 2x^(2)-5xy+2y^(2)=0 represents two sides of triangle whose centroid is (1,1) then the equation of the third side is (A)x+y-3=0 (B) x-y-3=0 (C) x+y+3=0 (D) x-y+3=0

In a triangle ABC, if A is (2,-1), and 7x-10y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector,respectively, drawn from B ,then the equation of BC is (a) a+y+1=0(b)5x+y+17=0 (c) 4x+9y+30=0( d) x-5y-7=0

If two sides of a triangle are represented by 2x-3y+4=0 and 3x+2y-3=0 , then its orthocentre lies on the line : (A) x-y+ 8/15 = 0 (B) 3x-2y+1=0 (C) 9x-y+9/13 = 0 (D) 4x+3y+5/13=0

The center of a rectangular hyperbola lies on the line y=2x. If one of the asymptotes is x+y+c=0, then the other asymptote is 6x+3y-4c=0 (b) 3x+6y-5c=03x-6y-c=0 (d) none of these