If pulley is ideal and string is massless then reading of weighing machine is `(5x)/(3)kg` then calculate `x. : (g = 10 m//s^(2))`

All the pulleys are ideal, string is massless then rate of work done by gravity at the given instant is (-x xx 10^(2))W then calculate x :

All the pulleys are ideal, string is massless then rate of work done by gravity at the given instant is (-x xx 10^(2))W then calculate x :

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a= 2 m//s^(2), v = - 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = - 2 m//s^(2) , v= - 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) ,v = 0

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = - 2 m//s^(2) , v = 0

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 0 , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a=0, v = 0

The elevator is going up with an acceleration of g//10 the pulley and the string are light and the pulley is smooth. If reading of spring balance shown is 0.8x Calculate x. (Take g=10m//s^(2))