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A cup (BcapC)= ……….....

A `cup` (B`cap`C)= ………..

A

`(AcupB)cap(AcupC)`

B

`(AcapB)cup(AcapC)`

C

`(AcupB)capC`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
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