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Sum of the areas of two squares is 468 m...

Sum of the areas of two squares is 468 `m^(2)` If the difference of their perimeters is 24m, find the sides of the two squares.

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The correct Answer is:
`:. "Side of the first square = 72/4 = 18m. (or) :. "Side of the second square" = 48/4 = 12m.`
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VGS PUBLICATION-BRILLIANT-QUADRATIC EQUATIONS-EXERCISE 5.3
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