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(x - alpha)(x - beta) = 0 "then"...

`(x - alpha)(x - beta) = 0 "then"`

A

`x^(2) - (alpha) x + beta = 0`

B

`x^(2) - (alpha + beta) x + alpha beta = 0`

C

`alphax^(2) - x beta + alpha beta = 0`

D

none

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The correct Answer is:
B
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