[(6x-4y+3)dx-(3x-2y+1)dy=0;" given "y=4],[x=2]

Find the paraticular solutions of the following equations: (6x-4y+3)dx-(3x-2y+1)dy=0 , given y=4, when x=2

(2x -2y+3) dx -(x-y+1) dy=0 , " when" x=0, y=1

(x^3+3x y^2)dx+(y^3+3x^2y)dy=0

(x^(3)+xy^(4))dx+2y^(3)dy=0

Solve (4x-6y+3)dy+(2x-3y-1)dx=0

The solution of the different equation (2x - 4y + 3)(dy)/(dx) + (x - 2y + 1) = 0 is

(2x+4y+3)(dy)/(dx)=2y+x+1