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If sum(n-1)^(2013)"tan"(theta/(2^n))s ...

If `sum_(n-1)^(2013)"tan"(theta/(2^n))s e c(theta/(2^(n-1)))=tan(theta/(2^a))-tan(theta/(2^b))` then `(b+a)` equals (a)2014 (b) 2012 (c) 2013 (d) 2014

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