A toroid has number of turns per unit length `n`, current `i`, then the magnetic field is

A wire is wound on a long rod of material of relative permeability mu_(r) = 4000 to make a solenoid. If the current through the wire is 5 A and number of turns per unit length is 1000 per metre, then the magnetic field inside the solenoid is

A wire is wound on a long rod of material of relative permeability mu_(r)=4000 to make a solenoid.If the current through the wire is 5A and number of turns per unit length is 1000 per metre,then the magnetic field inside the solenoid is:

A wire is wound on a long rod of material of relative permeability mu_(r) = 4000 to make a solenoid. If the current through the wire is 5 A and number of turns per unit length is 1000 per metre, then the magnetic field inside the solenoid is

A long solenoid has a radius a and number of turns per unit length is n . If it carries a current i, then the magnetic field on its axis is directly proportional to

A long solenoid has a radius a and number of turns per unit length is n . If it carries a current i, then the magnetic field on its axis is directly proportional to

A long solenoid carrying a current produces a magnetic field B along its axis. IF the current is doubled and the number of turns per unit length is halved, the new value of he magnetic field is-

In a solenoid, the corrent flowing through the wire is I and number of turns per unit length is n. This gives a magnetic field B inside the solenoid. If number of turn per unit length is increased to 2n, what will be the value of magnetic field in the solenoidgt