vy log(x+y)=1quad 18

Suppose x,y,z=0 and are not equal to 1 and log x+log y+log z=0. Find the value of (1)/(x^(log y))+(1)/(log z)quad (1)/(y^(log z))+(1)/(log x)quad (1)/(z^(log x))+(1)/(log y)

If log ((x+y)/3)=1/2 (log x +log y) then find the value of x/y+y/x

If log ((x+y)/3)=1/2 (log x +log y) then find the value of x/y+y/x

If log ((x+y)/3)=1/2 (log x +log y) then find the value of x/y+y/x

If log ((x+y)/3)=1/2 (log x +log y) then find the value of x/y+y/x

If log((x+y)/5) = 1/2 (log x + log y) , then show that x/y + y/x = 23 .

If x^(18)= y^(21) = z^(28) , then 3, 3log_(y)x, 3log_(z)y, 7 log_(x)z are in :

(dy)/(dx)=(xy)/((1-x)(1+y)) A) x+y+log[y(1-x)]=c B) x+y+log[x(1-y)]=c C) x+y+log(x+y)=c D) y-x+log[x(1-y)]=c

If log_(12)18=x and log_(24)4=y then find the value of xy-(2x+5y)+4

y The solution of the differential equation (dy)/(dx)=(x+y)/(x) satisfying the condition y(1)=1 is (1) y=ln x+x (2) quad y=x ln x+x^(2)y=x ln x+x^(2)y=x ln x+x