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2.^(n)P(3)=n+1P(3)...

2.^(n)P_(3)=n+1P_(3)

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2.^(n)P_(3)=^(n+1)P_(3)

if ^(n)P_(5):^(n)P_(3)=2:1, then n

prove that 1P_(1)+2.2P_(2)+3.3P_(3)+.......+n.nP_(n)=(n+1)P_(n+1)-1

Find n if .^(n-)P_(3): .^(n)P_(4) = 1:9 .

Find the value of n from each of the following: (i) 10 .^(n)P_(6) = .^(n+1)P_(3) (ii) 16.^(n)P_(3) = 13 .^(n+1)P_(3)

The value of ""^(n)P_(1)+(""^(n)P_(2))/(2!)+(""^(n)P_(3))/(3!)+......+(""^(n)P_(n))/(n!)

Prove that 1+1* ""^(1)P_(1)+2* ""^(2)P_(2)+3* ""^(3)P_(3) + … +n* ""^(n)P_(n)=""^(n+1)P_(n+1).